What is the enthalpy change for the reaction: C2H2(g) + 5/2O2(g) → 2CO2(g) + H2O(g) given the following chemical equations: (1) C2H2(g) + 5/2O2(g) → 2CO(g) + H2O(g) ΔH = -636.1 kJ/mol; (2) CO(g) + 1/2O2(g) → CO2(g) ΔH = -283.0 kJ/mol; (3) C2H2(g) + 5/2O2(g) → 2CO2(g) + H2O(g) ΔH = -1299.5 kJ/mol?




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