The composition of two functions, $f$ and $g$, evaluated at the input $x$. This represents the result of first applying the function $g$ to the input $x$, and then applying the function $f$ to the result of $g(x)$.
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The notation $(f ∘ g)(x)$ represents the composition of the functions $f$ and $g$, where the output of $g(x)$ becomes the input for $f(x)$.
Composing functions allows you to create new functions by combining the operations of existing functions.
The domain of the composite function $(f ∘ g)(x)$ is the set of all $x$ values for which $g(x)$ is in the domain of $f$.
Composing functions is not commutative, meaning $(f ∘ g)(x) \neq (g ∘ f)(x)$ in general.
Inverse functions can be used to 'undo' the effect of a composite function, so that $(f ∘ g)^{-1}(x) = g^{-1}(f^{-1}(x))$.
Review Questions
Explain the process of evaluating a composite function $(f ∘ g)(x)$.
To evaluate a composite function $(f ∘ g)(x)$, you first evaluate the inner function $g(x)$, and then use the result as the input for the outer function $f(x)$. This means that you are applying the function $f$ to the output of $g$. The final result is the value of $f(g(x))$, which represents the composition of the two functions.
Describe the relationship between the domains of the component functions $f$ and $g$ and the domain of the composite function $(f ∘ g)(x)$.
The domain of the composite function $(f ∘ g)(x)$ is the set of all $x$ values for which $g(x)$ is in the domain of $f$. In other words, the composite function $(f ∘ g)(x)$ is defined only for those $x$ values where the output of $g(x)$ is a valid input for the function $f$. This means that the domain of the composite function is the intersection of the domains of the component functions $f$ and $g$.
Explain why the composition of functions is generally not commutative, and provide an example to illustrate this.
The composition of functions is generally not commutative, meaning that $(f ∘ g)(x) \neq (g ∘ f)(x)$ in most cases. This is because the order in which the functions are applied matters. When composing $f$ and $g$, the output of $g(x)$ becomes the input for $f(x)$, whereas when composing $g$ and $f$, the output of $f(x)$ becomes the input for $g(x)$. These two different sequences of operations can lead to different results. For example, if $f(x) = x^2$ and $g(x) = x + 1$, then $(f ∘ g)(x) = (x + 1)^2$, but $(g ∘ f)(x) = \sqrt{x} + 1$, which are not equal.