Honors Pre-Calculus

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Combinations for Group Selection

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Honors Pre-Calculus

Definition

Combinations for group selection refers to the mathematical concept of determining the number of unique ways to choose a specific number of items from a larger set, without regard to order. This is a fundamental principle in the field of counting and probability, particularly in the context of 11.5 Counting Principles.

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5 Must Know Facts For Your Next Test

  1. The formula for calculating the number of combinations is $\binom{n}{k} = \frac{n!}{k!(n-k)!}$, where $n$ is the total number of items and $k$ is the number of items being selected.
  2. Combinations are used to determine the number of unique subsets or groups that can be formed from a larger set, without considering the order of the items within the subsets.
  3. The binomial coefficient $\binom{n}{k}$ is read as 'n choose k' and represents the number of ways to select $k$ items from a set of $n$ items.
  4. Combinations are commonly used in probability calculations, such as determining the probability of obtaining a specific outcome in a series of independent events.
  5. The number of combinations is always less than or equal to the number of permutations for the same set of items, as permutations take into account the order of the items.

Review Questions

  • Explain the difference between combinations and permutations, and provide an example of each.
    • Combinations and permutations are both ways of counting the number of possible arrangements or selections from a set of items, but they differ in the importance of order. Combinations focus on the number of unique subsets or groups that can be formed, without regard to the order of the items within the subsets. For example, the combination of choosing 3 items from a set of 5 items is $\binom{5}{3} = 10$, as there are 10 unique ways to select 3 items from the set of 5. In contrast, permutations consider the order of the items, and the number of permutations of 3 items from a set of 5 items is $5 \times 4 \times 3 = 60$, as the order of the 3 items selected matters.
  • Describe the formula for calculating the number of combinations and explain the meaning of each variable in the formula.
    • The formula for calculating the number of combinations is $\binom{n}{k} = \frac{n!}{k!(n-k)!}$, where: - $n$ is the total number of items in the set - $k$ is the number of items being selected - $n!$ is the factorial of $n$, which represents the total number of permutations of the $n$ items - $k!$ is the factorial of $k$, which represents the total number of permutations of the $k$ items being selected - $(n-k)!$ is the factorial of $(n-k)$, which represents the total number of permutations of the remaining $(n-k)$ items not being selected The formula essentially calculates the number of unique ways to select $k$ items from a set of $n$ items, without regard to the order of the selected items.
  • Explain how combinations are used in probability calculations and provide an example.
    • Combinations are frequently used in probability calculations, particularly when determining the probability of obtaining a specific outcome in a series of independent events. For example, if you have a deck of 52 playing cards and you want to calculate the probability of drawing 5 specific cards (e.g., the Ace of Spades, the 3 of Hearts, the Queen of Diamonds, the 7 of Clubs, and the 2 of Hearts) without regard to the order in which they are drawn, you would use the combination formula. The number of ways to choose 5 cards from a deck of 52 cards is $\binom{52}{5}$, which is approximately 2.6 million. The probability of drawing those 5 specific cards would then be $\frac{\binom{52}{5}}{\binom{52}{5}}$, which is 1 in 2.6 million. This illustrates how combinations are used to determine the number of possible outcomes in probability calculations.

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