Fundamental Theorem of Calculus, Part 1
from class: Calculus II Definition The Fundamental Theorem of Calculus, Part 1 states that if $F$ is an antiderivative of $f$ on an interval $[a, b]$, then the integral of $f$ from $a$ to any point $x$ in that interval is equal to $F(x) - F(a)$. It links the process of differentiation and integration.
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Predict what's on your test 5 Must Know Facts For Your Next Test The theorem provides a way to evaluate definite integrals using antiderivatives. If $f$ is continuous on $[a, b]$, then there exists a function $F$ such that $F'(x) = f(x)$ for all $x$ in $(a, b)$. The integral $\int_a^b f(t) \, dt = F(b) - F(a)$ where $F$ is any antiderivative of $f$. This theorem is fundamental because it shows that differentiation and integration are inverse processes. The Fundamental Theorem of Calculus connects the concept of an area under a curve with antiderivatives. Review Questions What does the Fundamental Theorem of Calculus, Part 1 state about the relationship between integration and differentiation? How can you use an antiderivative to evaluate a definite integral? What conditions must be satisfied for the Fundamental Theorem of Calculus, Part 1 to hold? "Fundamental Theorem of Calculus, Part 1" also found in:
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