🔟Elementary Algebra Unit 8 – Rational Expressions and Equations

Rational expressions and equations are fundamental concepts in algebra that involve fractions with polynomials. They're crucial for understanding more advanced math topics and real-world applications. This unit covers simplifying expressions, performing operations, solving equations, and graphing rational functions. Students will learn to manipulate these expressions, find common denominators, and solve complex problems. They'll also explore the behavior of rational functions, including asymptotes and intercepts, which are essential for graphing and analyzing their properties.

Key Concepts

  • Rational expressions are fractions with polynomials in the numerator and denominator
  • Rational equations are equations that contain rational expressions
  • Rational functions are functions that can be written as a ratio of two polynomials
  • Domain of a rational expression or function consists of all real numbers except those that make the denominator equal to zero
  • Simplifying rational expressions involves factoring the numerator and denominator and canceling common factors
  • Operations with rational expressions include addition, subtraction, multiplication, and division
  • Solving rational equations involves finding the values of the variable that make the equation true
  • Graphing rational functions requires finding the domain, vertical asymptotes, horizontal asymptotes, x-intercepts, and y-intercept

Simplifying Rational Expressions

  • Factor the numerator and denominator completely
    • Use factoring techniques such as common factors, difference of squares, and trinomial factoring
  • Cancel common factors in the numerator and denominator
    • Factors can be canceled if they appear in both the numerator and denominator
  • Simplify any remaining terms in the numerator and denominator
  • Check the domain of the simplified rational expression
    • The domain consists of all real numbers except those that make the denominator equal to zero
  • Example: Simplify x24x25x+6\frac{x^2-4}{x^2-5x+6}
    • Factor the numerator: x24=(x+2)(x2)x^2-4 = (x+2)(x-2)
    • Factor the denominator: x25x+6=(x2)(x3)x^2-5x+6 = (x-2)(x-3)
    • Cancel the common factor (x2)(x-2): x+2x3\frac{x+2}{x-3}
    • The domain is all real numbers except x=3x=3

Operations with Rational Expressions

  • Addition and subtraction require a common denominator
    • Find the least common multiple (LCM) of the denominators
    • Multiply the numerator and denominator of each rational expression by the appropriate factor to obtain the common denominator
    • Add or subtract the numerators and keep the common denominator
  • Multiplication involves multiplying the numerators and denominators separately
    • Simplify the resulting rational expression by canceling common factors
  • Division of rational expressions is performed by multiplying the first expression by the reciprocal of the second expression
    • Simplify the resulting rational expression by canceling common factors
  • Example: Simplify 2x+1+3x1\frac{2}{x+1} + \frac{3}{x-1}
    • LCM of the denominators is (x+1)(x1)(x+1)(x-1)
    • 2x+1x1x1+3x1x+1x+1=2(x1)(x+1)(x1)+3(x+1)(x+1)(x1)\frac{2}{x+1} \cdot \frac{x-1}{x-1} + \frac{3}{x-1} \cdot \frac{x+1}{x+1} = \frac{2(x-1)}{(x+1)(x-1)} + \frac{3(x+1)}{(x+1)(x-1)}
    • 2x2+3x+3(x+1)(x1)=5x+1x21\frac{2x-2+3x+3}{(x+1)(x-1)} = \frac{5x+1}{x^2-1}

Solving Rational Equations

  • Multiply both sides of the equation by the least common multiple (LCM) of the denominators to clear the fractions
  • Simplify the resulting equation
  • Solve the equation using appropriate techniques (factoring, quadratic formula, etc.)
  • Check the solutions by substituting them back into the original equation
    • Reject any solutions that make the denominators equal to zero
  • Example: Solve 2x+1=3x1\frac{2}{x+1} = \frac{3}{x-1}
    • Multiply both sides by the LCM (x+1)(x1)(x+1)(x-1): 2(x1)=3(x+1)2(x-1) = 3(x+1)
    • Simplify: 2x2=3x+32x-2 = 3x+3
    • Solve: x=5-x = 5, so x=5x = -5
    • Check the solution: 25+1=351\frac{2}{-5+1} = \frac{3}{-5-1} is true, and the denominators are not zero

Graphing Rational Functions

  • Find the domain of the rational function
    • The domain consists of all real numbers except those that make the denominator equal to zero
  • Find the vertical asymptotes
    • Vertical asymptotes occur at the x-values that make the denominator equal to zero
  • Find the horizontal asymptote (if it exists)
    • Compare the degrees of the numerator and denominator
      • If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is y = 0
      • If the degrees are equal, the horizontal asymptote is y = the leading coefficient of the numerator divided by the leading coefficient of the denominator
      • If the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote
  • Find the x-intercepts (if they exist)
    • Set the numerator equal to zero and solve for x
  • Find the y-intercept (if it exists)
    • Substitute x = 0 into the rational function and simplify
  • Plot the points and asymptotes, and sketch the graph
  • Example: Graph f(x)=x+1x2f(x) = \frac{x+1}{x-2}
    • Domain: all real numbers except x = 2
    • Vertical asymptote: x = 2
    • Horizontal asymptote: y = 1 (degrees are equal, 11=1\frac{1}{1} = 1)
    • x-intercept: x = -1
    • y-intercept: f(0)=12=12f(0) = \frac{1}{-2} = -\frac{1}{2}

Applications and Word Problems

  • Identify the given information and the unknown quantity
  • Set up a rational equation or expression based on the problem statement
  • Solve the equation or simplify the expression
  • Interpret the solution in the context of the problem
  • Example: A group of friends decides to split the cost of a 60gift.Ifeachpersoncontributes60 gift. If each person contributes 5 less than the original share, two more people can join the group. How many people were in the group originally?
    • Let x be the number of people in the group originally
    • The original share per person is 60x\frac{60}{x}
    • The new share per person is 60x+2=60x5\frac{60}{x+2} = \frac{60}{x} - 5
    • Set up the equation: 60x+2=60x5\frac{60}{x+2} = \frac{60}{x} - 5
    • Solve the equation: x = 6
    • Interpret the solution: There were 6 people in the group originally

Common Mistakes and How to Avoid Them

  • Forgetting to factor the numerator and denominator completely before canceling common factors
    • Always factor the numerator and denominator as much as possible
  • Canceling terms instead of factors
    • Only cancel factors that appear in both the numerator and denominator
  • Forgetting to find the LCM when adding or subtracting rational expressions
    • Always find the LCM of the denominators and adjust the numerators accordingly
  • Not checking the domain of the rational expression or function
    • Always consider the values that make the denominator equal to zero and exclude them from the domain
  • Forgetting to check the solutions of rational equations
    • Always substitute the solutions back into the original equation to verify their validity and reject any solutions that make the denominators equal to zero
  • Misidentifying the horizontal asymptote
    • Compare the degrees of the numerator and denominator to determine the existence and equation of the horizontal asymptote
  • Plotting the vertical asymptote as a vertical line
    • Vertical asymptotes are not part of the graph; they represent the x-values that the graph approaches but never reaches

Practice Problems and Solutions

  1. Simplify x2+3xx24\frac{x^2+3x}{x^2-4}

    • Solution: x(x+3)(x+2)(x2)=xx2\frac{x(x+3)}{(x+2)(x-2)} = \frac{x}{x-2}, domain: all real numbers except x = 2
  2. Perform the operation and simplify: 3x+21x1\frac{3}{x+2} - \frac{1}{x-1}

    • Solution: 3(x1)(x+2)(x1)1(x+2)(x+2)(x1)=3x3x2(x+2)(x1)=2x5x2+x2\frac{3(x-1)}{(x+2)(x-1)} - \frac{1(x+2)}{(x+2)(x-1)} = \frac{3x-3-x-2}{(x+2)(x-1)} = \frac{2x-5}{x^2+x-2}
  3. Solve the rational equation: 2x1+3x+2=5x+1\frac{2}{x-1} + \frac{3}{x+2} = \frac{5}{x+1}

    • Solution: x = -5 or x = 4, but x = -2 is rejected because it makes a denominator equal to zero
  4. Graph the rational function: f(x)=x1x+3f(x) = \frac{x-1}{x+3}

    • Solution: Domain: all real numbers except x = -3, Vertical asymptote: x = -3, Horizontal asymptote: y = 1, x-intercept: x = 1, y-intercept: f(0)=13f(0) = -\frac{1}{3}
  5. A rectangle's length is 3 units more than its width. If the rectangle's area is 10 square units, find its dimensions.

    • Solution: Let the width be x units. Then, the length is x + 3 units. Set up the equation: x(x+3)=10x(x+3) = 10. Solve the equation: x = 1 or x = 2. The dimensions are either 1 unit by 4 units or 2 units by 5 units.


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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.