6.4 Conservation of Angular Momentum

Conservation of angular momentum is a fundamental principle in physics that describes how rotating systems behave. It states that the total angular momentum of a closed system remains constant unless acted upon by external torques.

This principle has wide-ranging applications, from understanding the motion of celestial bodies to explaining the behavior of figure skaters. It allows us to predict changes in rotational speed when mass distribution changes, and analyze collisions involving rotating objects.

Sum of Angular Momenta

The total angular momentum of a system is found by combining the individual angular momenta of each part about a specific rotational axis. 🔄

• Angular momentum follows the principle of superposition - the total effect equals the sum of individual contributions
• For a system of particles, the total angular momentum is $L_{total} = \sum L_i = \sum r_i \times p_i$
• For extended objects, we can integrate over all mass elements: $L = \int r \times v \, dm$
• The direction of angular momentum follows the right-hand rule, perpendicular to both position and momentum vectors

When analyzing complex systems like planetary motion or rotating machinery, this summation approach allows us to track how angular momentum is distributed throughout the system.

Changes in Angular Momentum

Angular momentum can only change when an external torque acts on the system.

• According to Newton's second law for rotation: $\tau_{net} = \frac{d\vec{L}}{dt}$
• When two objects interact, they exert equal and opposite angular impulses on each other (Newton's third law)
• By carefully defining our system boundaries, we can create a closed system with no external torques
• In a closed system, the total angular momentum remains constant even as it redistributes among components
• Any change in a system's total angular momentum equals the net angular impulse applied: $\Delta \vec{L} = \int \vec{\tau} \, dt$

This principle explains why a spinning top eventually slows down (due to friction with the surface creating an external torque) while planets can orbit for billions of years with minimal change (negligible external torques).

Angular Impulse

Angular impulse represents the cumulative effect of torque applied over time, changing an object's angular momentum.

• Mathematically defined as: $\vec{J} = \int \vec{\tau} \, dt$
• For constant torque: $\vec{J} = \vec{\tau} \Delta t$
• Units are $\text{kg} \cdot \text{m}^2/\text{s}$ (same as angular momentum)
• According to the impulse-momentum theorem for rotation: $\vec{J} = \Delta \vec{L}$
• Angular impulse is a vector quantity with the same direction as the torque that produced it

When a baseball bat strikes a ball, the angular impulse delivered depends on both the magnitude of the torque and how long the bat remains in contact with the ball.

Constant Angular Momentum

In a closed system with no external torques, the total angular momentum remains constant. 🌀

• Expressed mathematically as: $\vec{L}_i = \vec{L}_f$ or $I_i\omega_i = I_f\omega_f$
• Angular momentum can redistribute among components, but the total sum stays the same
• This principle applies to all scales, from atomic particles to galaxies
• The conservation law holds in all reference frames, making it a fundamental physical principle

A classic demonstration involves a person sitting on a rotating stool holding weights. When they extend their arms, their rotation slows; when they pull their arms in, they spin faster—all while maintaining constant angular momentum.

Angular Speed in Nonrigid Systems

When a system's mass distribution changes relative to its rotation axis, its angular speed adjusts to conserve angular momentum.

• The relationship is governed by: $I_i\omega_i = I_f\omega_f$
• When moment of inertia decreases (mass moves closer to axis), angular speed increases
• When moment of inertia increases (mass moves away from axis), angular speed decreases 📏
• The product $I\omega$ always remains constant in the absence of external torques

Figure skaters utilize this principle during spins. By pulling their arms and leg close to their body (reducing $I$), they dramatically increase their rotation speed ($\omega$) while maintaining the same angular momentum.

Angular Impulse Effects

Angular impulse determines how a system's rotation changes during interactions.

• For constant torque: $\Delta \vec{L} = \vec{\tau} \Delta t$
• For variable torque: $\Delta \vec{L} = \int \vec{\tau} \, dt$
• The final angular momentum equals initial angular momentum plus angular impulse: $\vec{L}_f = \vec{L}_i + \vec{J}$
• Angular speed after impulse can be calculated as: $\omega_f = \frac{L_i + J}{I_f}$

This concept explains phenomena like how a falling cat can reorient itself to land on its feet without violating conservation of angular momentum, by changing its body configuration in a specific sequence.

Practice Problem 1: Figure Skater Spin

Solution

We can apply conservation of angular momentum since there are no external torques acting on the skater:

$L_i = L_f$ $I_i \omega_i = I_f \omega_f$

Rearranging to solve for the final angular velocity: $\omega_f = \frac{I_i \omega_i}{I_f}$

Substituting the given values: $\omega_f = \frac{4.0 \text{ kg·m²} \times 2.0 \text{ rad/s}}{1.6 \text{ kg·m²}}$ $\omega_f = \frac{8.0 \text{ kg·m²·rad/s}}{1.6 \text{ kg·m²}}$ $\omega_f = 5.0 \text{ rad/s}$

The skater's angular velocity increases from 2.0 rad/s to 5.0 rad/s when she pulls her arms in, demonstrating how decreasing moment of inertia increases angular velocity when angular momentum is conserved.

Practice Problem 2: Angular Impulse

Solution

To solve this problem, we need to find the change in angular momentum due to the angular impulse, then calculate the final angular velocity.

Step 1: Calculate the initial angular momentum. $L_i = I\omega_i = 2.5 \text{ kg·m²} \times 10 \text{ rad/s} = 25 \text{ kg·m²/s}$

Step 2: Calculate the angular impulse. $J = \tau \Delta t = 5.0 \text{ N·m} \times 3.0 \text{ s} = 15 \text{ kg·m²/s}$

Step 3: Find the final angular momentum. $L_f = L_i + J = 25 \text{ kg·m²/s} + 15 \text{ kg·m²/s} = 40 \text{ kg·m²/s}$

Step 4: Calculate the final angular velocity. $\omega_f = \frac{L_f}{I} = \frac{40 \text{ kg·m²/s}}{2.5 \text{ kg·m²}} = 16 \text{ rad/s}$

The wheel's angular velocity increases from 10 rad/s to 16 rad/s due to the applied torque.